x^2+1.875x-0.25=0

Solution for x^2+1.875x-0.25=0 equation:

x^2+1.875x-0.25=0

a = 1; b = 1.875; c = -0.25;
Δ = b2-4ac
Δ = 1.8752-4·1·(-0.25)
Δ = 4.515625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.875)-\sqrt{4.515625}}{2*1}=\frac{-1.875-\sqrt{4.515625}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.875)+\sqrt{4.515625}}{2*1}=\frac{-1.875+\sqrt{4.515625}}{2}
$